studio
2023.10
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- Working with Input and Output arguments
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Working with Input and Output
arguments
Studio User Guide
Last updated Dec 19, 2024
Working with Input and Output arguments
Learn how to efficiently handle input and output arguments
in coded automations, including their integration when invoked in low-code
workflows.
Using nested classes as workflow arguments is not supported. Classes used as arguments must be directly defined within a namespace.
When designing coded automations, you can add input, output, and In/Out arguments
alongside the entry point
Execute
method. Irrespective of their
definition order, In/Out arguments are placed at the end of the method's argument
list.
Check out the scenarios below to understand how to add arguments to your coded automations.
Adding input parameters
- To add input parameters, define them after the name of the entry point method.
- For example, you have a coded automation that represents a loan application
taking input arguments only. The needed input arguments are the
customerName
,loanAmount
,loanRate
andloanTerm
. Check out the code snippet below:public void Execute (string customerName, decimal loanAmount, double loanRate, int loanTerm)
public void Execute (string customerName, decimal loanAmount, double loanRate, int loanTerm)
Adding output parameters
- To add output parameters, define
them before the name of the entry point method.
Note: If the method returns a single parameter, it is automatically named
Output
by default, and you can't rename it. - For example, you have a coded automation that approves or denies a loan
application based on the loan rate. This automation requires an input argument
for the loan rate (
loanRate
), and an output argument showing if the loan application was approved or denied (loanApproved
). Check out the code snippet below:public bool Execute (int loanRate)
public bool Execute (int loanRate) - Let's take another example that outputs two parameters. Suppose you have a coded
automation that returns the approved loan amount
(
LoanAmountApproved
) and if the loan was approved (IsLoanApproved
), based on the loan rate (LoanRate
). Check out the code snippet below:public (int LoanAmountApproved, bool IsLoanApproved) Execute(int LoanRate)
public (int LoanAmountApproved, bool IsLoanApproved) Execute(int LoanRate)
Adding In/Out parameters
- To add an argument of type In/Out, define the same argument both before and after the name of the entry point method.
- For example, you have a coded automation that takes an initial loan amount
(
loanAmount
) and an interest rate (interestRate
) as input and then calculates the updated loan amount after applying the interest rate and returns it. Also, it returns an argument stating the type of financial need that this loan amount would require.Check out the code snippet below:public (double loanAmount, string financialNeed) Execute (double interestRate, double loanAmount)
public (double loanAmount, string financialNeed) Execute (double interestRate, double loanAmount)
- Create a coded automation that
takes an initial loan amount (
loanAmount
) and an interest rate (interestRate
) as input and then calculates the updated loan amount after applying the interest rate and returns it.For this coded automation you should declare the entry point method aspublic double Execute (double interestRate, double loanAmount)
- Add an Invoke Workflow File activity in a low-code automation and offer the path to the coded automation you previously created.
- Click Import Arguments and
check the imported arguments.
For the coded automation offered as an example, you should have the following imported arguments:
Name Direction Type Value loanAmount
In/Out Double
10,000 interestRate
In Double
5 Manually add the arguments that don't appear as imported arguments.
Note: For Cross-platform projects, the arguments that you add to a
coded automation are automatically imported in a low-code automation when you invoke
them using the Invoke Workflow File activity.